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std::exp

STD::exp

Defined in header
float exp( float arg (1)
double exp( double arg (2)
long double exp( long double arg (3)
double exp( Integral arg (4)(since C++11)

计算e%28欧拉%27S数,2.7182818%29提高到给定的功率arg...

4%29一组过载或接受任意参数的函数模板积分型等于2%29%28double29%。

参数

arg-value of floating-point or Integral type

返回值

如果没有错误发生,基地-e指数arg%28耳

%29被返回。

如果溢出导致范围错误,+HUGE_VAL,,,+HUGE_VALF,或+HUGE_VALL会被归还。

如果由于下流而发生范围错误,则返回舍入%29后的正确结果%28。

错误处理

错误按数学[医]错误处理...

如果实现支持ieee浮点算法%28IEC 60559%29,

  • 如果参数为±0,则返回1

  • 如果参数为-∞,则返回+0。

  • 如果参数为+∞,则返回+∞

  • 如果参数为nan,则返回nan。

注记

适用于ieee兼容的类型。double,如果709.8<arg则保证溢出,如果arg<-708.4则保证下溢。

二次

#include <iostream> #include <cmath> #include <cerrno> #include <cstring> #include <cfenv> #pragma STDC FENV_ACCESS ON int main() { std::cout << "exp(1) = " << std::exp(1) << '\n' << "FV of $100, continuously compounded at 3% for 1 year = " << 100*std::exp(0.03) << '\n'; // special values std::cout << "exp(-0) = " << std::exp(-0.0) << '\n' << "exp(-Inf) = " << std::exp(-INFINITY) << '\n'; // error handling errno=0; std::feclearexcept(FE_ALL_EXCEPT std::cout << "exp(710) = " << std::exp(710) << '\n'; if(errno == ERANGE) std::cout << " errno == ERANGE: " << std::strerror(errno) << '\n'; if(std::fetestexcept(FE_OVERFLOW)) std::cout << " FE_OVERFLOW raised\n"; }

二次

可能的产出:

二次

exp(1) = 2.71828 FV of $100, continuously compounded at 3% for 1 year = 103.045 exp(-0) = 1 exp(-Inf) = 0 exp(710) = inf errno == ERANGE: Numerical result out of range FE_OVERFLOW raised

二次

另见

exp2 (C++11)returns 2 raised to the given power (2x) (function)
expm1 (C++11)returns e raised to the given power, minus one (ex-1) (function)
logcomputes natural (base e) logarithm (to base e) (ln(x)) (function)
exp(std::complex)complex base e exponential (function template)
exp(std::valarray)applies the function std::exp to each element of valarray (function template)

C.EXP文件

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