std::chrono::time_point::max
STD::时间::时间[医]要点:最大
static constexpr time_point max( | | |
---|
返回time_point
尽可能长的时间,即std::chrono::time_point
(std::chrono::duration::max())
...
参数
%280%29
返回值
最大可能time_point
...
例
二次
#include <chrono>
#include <vector>
#include <iostream>
int main()
{
std::chrono::time_point<std::chrono::system_clock> now =
std::chrono::system_clock::now(
std::vector<std::chrono::time_point<std::chrono::system_clock>> times {
now - std::chrono::hours(24),
now - std::chrono::hours(48),
now + std::chrono::hours(24),
};
std::chrono::time_point<std::chrono::system_clock> earliest =
std::chrono::time_point<std::chrono::system_clock>::max(
std::cout << "all times:\n";
for (const auto &time : times) {
std::time_t t = std::chrono::system_clock::to_time_t(time
std::cout << std::ctime(&t
if (time < earliest) earliest = time;
}
std::time_t t = std::chrono::system_clock::to_time_t(earliest
std::cout << "earliest:\n" << std::ctime(&t
}
二次
可能的产出:
二次
all times:
Sun Oct 7 19:06:48 2012
Sat Oct 6 19:06:48 2012
Tue Oct 9 19:06:48 2012
earliest:
Sat Oct 6 19:06:48 2012
二次
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