std::bit_and
STD:BIT[医]和
Defined in header | | |
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template< class T > struct bit_and; | | (until C++14) |
template< class T = void > struct bit_and; | | (since C++14) |
函数对象,用于按位执行和。有效呼叫operator&
论类型T
...
专门性
The standard library provides a specialization of std::bit_and when T is not specified, which leaves the parameter types and return type to be deduced. bit_and | bit_and | function object implementing x & y deducing argument and return types (class template specialization) | (since C++14) |
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bit_and<void> | function object implementing x & y deducing argument and return types (class template specialization) |
成员类型
Type | Definition |
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result_type(deprecated in C++17) | T |
first_argument_type(deprecated in C++17) | T |
second_argument_type(deprecated in C++17) | T |
成员函数
operator() | returns the result of bitwise AND of two arguments (public member function) |
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STD:BIT[医]操作员%28%29
T operator()( const T& lhs, const T& rhs ) const; | | (until C++14) |
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constexpr T operator()( const T& lhs, const T& rhs ) const; | | (since C++14) |
返回按位和lhs
和rhs
...
参数
lhs, rhs | - | values to compute bitwise AND of |
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返回值
结果lhs & rhs
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例外
%280%29
可能的实施
ConstT算子%28%29%28 const T&lhs,const T&rhs%29 const{返回lhs&rhs;}
*。
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