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规律表达 | Regular expressions

std::regex_error

STD::regex[医]误差

Defined in header
class regex_error;(since C++11)

定义抛出的异常对象类型以报告正则表达式库中的错误。

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继承图

成员函数

(constructor)constructs a regex_error object (public member function)
codegets the std::regex_constants::error_type for a regex_error (public member function)

继承自STD:例外

成员函数

(destructor) virtualdestructs the exception object (virtual public member function of std::exception)
what virtualreturns an explanatory string (virtual public member function of std::exception)

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#include <regex> #include <iostream> int main() { try { std::regex re("[a-b][a" } catch (const std::regex_error& e) { std::cout << "regex_error caught: " << e.what() << '\n'; if (e.code() == std::regex_constants::error_brack) { std::cout << "The code was error_brack\n"; } } }

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产出:

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regex_error caught: The expression contained mismatched [ and ]. The code was error_brack

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http://en.cppreference.com/w/cpp/regex/regex[医]误差