std::filesystem::path::root_directory
文件系统：：path：：root[医]目录
| path root_directory() const; | | (since C++17) |
|---|
返回路径的根目录。如果路径不包括根名称，则返回path()...
参数
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返回值
路径的根目录。
例外
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例
二次
#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
int main()
{
fs::path p = fs::current_path(
std::cout << "The current path " << p << " decomposes into:\n"
<< "root name " << p.root_name() << '\n'
<< "root directory " << p.root_directory() << '\n'
<< "relative path " << p.relative_path() << '\n';
}
二次
可能的产出：
二次
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:
root name "C:"
root directory "\"
relative path "Users\abcdef\Local Settings\temp"
二次
另见
| root_name | returns the root-name of the path, if present (public member function) |
|---|---|
| root_path | returns the root path of the path, if present (public member function) |
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