std::allocator::deallocate
STD::配售者::
void deallocate( T* p, std::size_t n | | |
---|
分配指针引用的存储。p
,它必须是以前调用的指针。allocate()
...
争论n
必须等于调用allocate()
原产p
否则,行为就没有定义。
打电话::
operator delete
(void*)
,但未具体说明何时和如何调用它。
参数
p | - | pointer obtained from allocate() |
---|---|---|
n | - | number of objects earlier passed to allocate() |
返回值
%280%29
另见
allocate | allocates uninitialized storage (public member function) |
---|---|
deallocate static | deallocates storage using the allocator (public static member function of std::allocator_traits) |
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